Find the number of ways in which 10 different flowers can be strung to form a garland so that 3 particular flowers are always together.
A
30240
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B
30420
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C
23400
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D
None of these
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Solution
The correct option is A 30240 Since 3 particulars flowers are together. Hence there can be total (10 - 3) + 1 = 8 flowers. These 8 flowers can be arranged 7! ways but the 3 flowers which are together can be arranged mutually in 3! ways. Hence, the required number of ways = 3! × 7! =6×5040=30240