Find the number of ways in which $12$ different flowers can be arranged in a garland so that $4$ particular flowers are never separate.

The correct option is D. 483840
Considering $4$ particular flowers as a single flower, we have $9$ flowers which can be arranged to form a garland in $8!$ ways.

But $4$ particular flowers can be arranged in $4!$ ways.

Hence, the required number of ways $=\frac{1}{2}(8!\times 4!)=\frac{1}{2}(40320\times 24)=483840$.