Question

Find the number of ways in which 15 players can be equally distributed into three different groups-A,B,C.

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

In distribution order is important.

The no. of ways in which mn different things can be distributed equally into m groups containing n things each =$\left[\frac{(mn!)}{(n!{)}^m}\right]$

Here, the groups are different, hence we do not divide by$3!.$

So, required no. of ways =$\left[\frac{(15!)}{(5!{)}^3}\right]$