Question

Find the number of ways in which $5$ boys and $4$ girls can be arranged on a circular table such that no two girls sit together and $2$ particular boys are always together?

• A. $276$
• B. $288$
• C. $296$
• D. $306$

Answer 1

The correct option is B $288$

According to question,

Total no. of boys=5,

No. of boys always together=2

Arrange in circular table=2+1+1+1 and No. of girls are not sitting together=4

Now,

The method of arranging in 4 sit in circular table.

ways- $4!.2!\times 4!$

$\begin{array}{c}=3!.2!\times 4!\\ =3\times 2\times 2\times 4\times 3\times 2\\ =6\times 2\times 24=288\end{array}$

So,the correct option is B.