Question

Find the .number of ways in which $5$ boys and $5$-girls be seated in .a row so that all the girls sit together and all the boys sit together.

Answer 1

The two groups of- boys and girls can be arranged in 2 ! ways and the group of 5 girls can be arranged amongst themselves in 5! ways and so the group of boys. Hence by fundamental theorem the number of ways is $2.5!.5!=$ $2(5!{)}^2$