Question

Find the number of ways in which 5 men and 4 women can be seated on a round table, so that no two women are together.

Answer 1

No. of men $=5$

No. of women$=4$

$(5-2)!4!$

$\Rightarrow 3!\times 4!$

$=3\times 2\times 1\times 4\times 3\times 2\times 1$

$=6\times 24$

$=144$