Find the number of ways in which $5$ persons $A, B, C, D, E$ can be seated round a table such that A and B always sit together?

24

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Solution

The correct option is B $12$
Consider $A B$ as single unit .
There are total 4 units and arrange them in a circular table.
It will be $(4 - 1)! = 3!$
and rest $" A B "$ can also arrange themselves.
Total number of permutations $= 3! \times 2$
$= 12$

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Find the number of ways in which 5 persons A,B,C,D,E can be seated round a table such that A and B always sit together?

The correct option is B 12Consider AB as single unit .There are total 4 units and arrange them in a circular table.It will be (4−1)!=3!and rest "AB" can also arrange themselves.Total number of permutations=3!×2=12

Find the number of ways in which $5$ persons $A, B, C, D, E$ can be seated round a table such that A and B always sit together?

The correct option is B $12$
Consider $A B$ as single unit .
There are total 4 units and arrange them in a circular table.
It will be $(4 - 1)! = 3!$
and rest $" A B "$ can also arrange themselves.
Total number of permutations $= 3! \times 2$
$= 12$