Find the number of ways in which the letters of the word 'MUNMUN' can be arranged so that no two alike letters are together?

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 30
Total number of ways of arranging MUNMUM $= \frac{6!}{2! 2! 2!} = 120$
If one of the pairs is together $= \frac{5!}{2! 2!} = 30$
So if no alike letters are together, no. of ways $= 120 - 30 \times 3 = 30$

Suggest Corrections

Similar questions

The number of ways in which any four letters can be selected from the word "EXAMINATION” if two letters are alike and other two letters are also alike.

The number of ways in which any four letters can be selected from the word "EXAMINATION” if two letters are alike and other two are distinct.

Q. The number of ways in which the letters of the word

^{'} A R R A N G E^{'}

can be arranged so that the two

R

's are never together is

Q. All the letters of the word

NUMBER

are arranged in different possible ways. What are the number of arrangements possible so that no two words are repeated?

Q. The number of ways in which the letters of the word

^{'} A R R A N G E^{'}

can be arranged so that the two

A

's are together but not two

R

's is

Join BYJU'S Learning Program

Find the number of ways in which the letters of the word 'MUNMUN' can be arranged so that no two alike letters are together?

The correct option is A 30Total number of ways of arranging MUNMUM =6!2!2!2!=120If one of the pairs is together =5!2!2!=30So if no alike letters are together, no. of ways =120−30×3=30

The correct option is A 30
Total number of ways of arranging MUNMUM $= \frac{6!}{2! 2! 2!} = 120$
If one of the pairs is together $= \frac{5!}{2! 2!} = 30$
So if no alike letters are together, no. of ways $= 120 - 30 \times 3 = 30$