Question

Find the number of ways of $4$ boys and $4$ girls can be seated in a row such that no two girls are seated together:

• A. 2881
• B. 2882
• C. 2880
• D. 2883

Answer 1

Answer: (C)

2880

$\text{Total no. of ways of arrangement}=8!$

$\therefore \text{No. of ways in which girls sit together}=5!\times 4!=2880\text{ways.}$