Find the number of ways of arranging m numbers out of 1,2,3,.....,n so that maximum is (n−2) and minimum is 2 (repetitions of numbers is allowed ) such that maximum and minimum both occur exactly once, (n>5,m>3) is
A
n−3Cm−2
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B
mC2(n−3)m−2
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C
m(m−1)(n−5)m−2
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D
nC2⋅nCm
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Solution
The correct option is An−3Cm−2 From the total number of numbers 1→n Only n−3 can be selected because 1,n−1,n cannot be included ,.So the no .of ways are n−3Cm