Question

Find the number of ways of distributing 8 identical balls in 3 distinct boxes so that no box is empty.

Answer 1

The total no of ways of dividing 8 identical balls in 3 distinct boxes so that none of the boxes is empty is
(8−1)C3−1=7C2(8−1)C3−1=7C2
⇒7!2!5!⇒7!2!5!
⇒7×6×5!2×5!= 21

Therefore Answer is 21