Find the number of ways of dividing $52$ cards among $4$ players eequally such that each gets exactly one Ace.

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Solution

$N u m b e r o f w a y s t o g i v e o n e a c e t o e a c h = 4 \times 3 \times 2 \times 1 = 24 T o t a l n u m b e r o f w a y s t o d i v i d e 52 c a r d s i n 4 p l a y e r s u c h t h a t e a c h g e t e x a c t l y o n e a c e = 24 \times {48_{C}}_{12} \times {36_{C}}_{12} \times {24_{C}}_{12} \times {12_{C}}_{12}$

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