The correct option is B 6720
Since rings are distinct, hence they can be named as R1,R2,R3,R4 and R5.
The ring R1 can be placed on any of the four fingers in 4 ways. The ring R2 can be placed on any of the four fingers in 5 ways since the finger in which R1 is placed now has 2 choices, one above the R1 and one below the ring R1.
Similarly R3, R4 and R5 can be arrange in 6, 7 and 8 ways respectively.
Hence, the required number of ways
=4×5×6×7×8=6720