Question

Find the number of ways of selecting $5$ members from a committee of $5$ men & $2$ women such that all women are always included.

Answer 1

Total 5 members have to be selected and 2 women are always included.
Hence total ways to select 5 members from committee is equal to select 3 out of 5 men.
${}^5{C}_3=5\times 2=10$