Find the number of ways to seat 'n' married couples around the table such that men and women are alternate.

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Solution

$n$ men and $n$ women

$2 n$ total person

Let a man is fixed so remaining places can be filled in $(n - 1)!$

Also, remaining women can be sited in $n!$

Total number of ways $= n! (n - 1)!$

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Find the number of ways to seat 'n' married couples around the table such that men and women are alternate.

n men and n women2n total personLet a man is fixed so remaining places can be filled in (n−1)!Also, remaining women can be sited in n!Total number of ways=n!(n−1)!

$n$ men and $n$ women

$2 n$ total person

Let a man is fixed so remaining places can be filled in $(n - 1)!$

Also, remaining women can be sited in $n!$

Total number of ways $= n! (n - 1)!$