Question

Find the number of words with or without meaning which can be made using all the letters of the word AGAIN. If these words are written as in a dictionary, what will be the ${50}^{th}$ word

• A. $NAAIG$
• B. $NAIAG$
• C. $NAAGI$
• D. $NIAAG$

Answer 1

Answer: (A)

$NAAIG$

Word starting with A $=4!=24$

Word starting with G $=\frac{4!}{2!}=\frac{24}{2}=12$

Word starting with I $=\frac{4!}{2!}=\frac{24}{2}=12$

49th Word starting with N = NAAGI

50th Word starting with N = NAAIG