Find the number such that when it is multiplied by $7$ and $17$ subtracted from the product result is same as when it is multiplied by $3$ and $19$ added to it.

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Solution

Let the number be $x$
then,
$7 x - 17 = 3 x + 19$
$4 x = 36$
$x = 9$
Hence, $9$ is the required answer.

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Find the number such that when it is multiplied by 7 and 17 subtracted from the product result is same as when it is multiplied by 3 and 19 added to it.

Let the number be xthen,7x−17=3x+194x=36x=9Hence, 9 is the required answer.

Find the number such that when it is multiplied by $7$ and $17$ subtracted from the product result is same as when it is multiplied by $3$ and $19$ added to it.

Let the number be $x$
then,
$7 x - 17 = 3 x + 19$
$4 x = 36$
$x = 9$
Hence, $9$ is the required answer.