Question

Find the number that is divisible by 1013 and 578 and leaves the same remainder

Answer 1

if a no is divisible by 1013 then it leaves zero remainder

I think your question Find the number that is divisible by 1013 and 578

there are many no.os that satisfy this condition
If you want to find the least no.
Just find the Highest common factor(1013,578)
1013=1013
578=2 *17²

Multiplying all common factors
HCF(1013,578)=1013*2 *17^2
=585514


5885514 is divisible by 1013,578

I will show you another example question similar to this
In case of remainders we have to substract remainders from the given no.s and find HCF Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively

• 19
• 17
• 13
• 9

Answer: Option B

Explanation:

Answer will be HCF of (400-9, 435-10, 541-14)

HCF of (391, 425, 527) = 17