Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

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Solution

The correct option is D 3
Let the number is $x$
Then,
$x + 17 = \frac{60}{x} x^{2} + 17 x - 60 = 0 (x + 20) (x - 3) = 0 x = 3, - 20 So x = 3 (as 3 is positive)$

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