Question

Find the number whose double is 45 greater than its half.

Answer 1

Let the required number = x

Double of it = 2x

and half of it = $\frac{x}{2}$

According to the condition,

$2x-\frac{x}{2}=45\Rightarrow \frac{4x-x}{2}=45\Rightarrow \frac{3}{2}x=45\Rightarrow x=\frac{45\times 2}{3}=30$

$\therefore$ Required number = 30