Question

Find the number whose double is $45$ greater then its half.

Answer 1

Let the number be $x$

Given the double of the number is $45$ greather than its half

$⟹2x=45+\frac{x}{2}$

$⟹2x-\frac{x}{2}=45$

$⟹\frac{3x}{2}=45$

$⟹x=30$

So the number is $30$