Find the number whose fifth part increased by 5 is equal to its fourth part diminished by 5.
Open in App
Solution
Let the number be x. According to the question we can write as (1/5)x+5=(1/4)x−5 On rearranging (1/5)x−(1/4)x=−5−5 (1/5)x−(1/4)x=−10 Now taking the L.C.M we get (4x−5x)/20=−10 Again by transposing X=200