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Question

Find the numbers of integers satisfying the following Inequalities
(i)x45x2+40
(ii)x42x2+630

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Solution

(i)x45x2+40
x44x2x2+40
x2(x24)1(x24)0
(x24)(x21)0
(x2)(x+2)(x1)(x+1)0
The critical points are {2,1,1,2}Z
Hence numbers of integers satisfying the inequalities=4
(ii)x42x2+630
x42x2+11+630
(x21)2+620
(x21)2+62
x21±62
Thus, there exists no integer.Hence numbers of integers satisfying the inequalities=0


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