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Byju's Answer
Standard XII
Mathematics
Local Maxima
Find the numb...
Question
Find the numbers of integers satisfying the following Inequalities
(
i
)
x
4
−
5
x
2
+
4
≤
0
(
i
i
)
x
4
−
2
x
2
+
63
≤
0
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Solution
(
i
)
x
4
−
5
x
2
+
4
≤
0
⇒
x
4
−
4
x
2
−
x
2
+
4
≤
0
⇒
x
2
(
x
2
−
4
)
−
1
(
x
2
−
4
)
≤
0
⇒
(
x
2
−
4
)
(
x
2
−
1
)
≤
0
⇒
(
x
−
2
)
(
x
+
2
)
(
x
−
1
)
(
x
+
1
)
≤
0
The critical points are
{
−
2
,
−
1
,
1
,
2
}
∈
Z
Hence numbers of integers satisfying the inequalities
=
4
(
i
i
)
x
4
−
2
x
2
+
63
≤
0
⇒
x
4
−
2
x
2
+
1
−
1
+
63
≤
0
⇒
(
x
2
−
1
)
2
+
62
≤
0
⇒
(
x
2
−
1
)
2
+
≤
−
62
⇒
x
2
−
1
≤
±
√
−
62
Thus, there exists no integer.Hence numbers of integers satisfying the inequalities
=
0
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