Question

Find the numerical value of the following:
$\frac{\cos {60}^o}{{\sin }^2{45}^o}-3\cot {45}^o+2\sin {90}^o$

Answer 1

we know that
$\cos {60}^o=\frac{1}{2};\sin {45}^o=\frac{1}{\sqrt{2}};\cot {45}^o=1;\sin {90}^o=1$
putting the values we get
$\frac{\frac{1}{2}}{{\left(\frac{1}{\sqrt{2}}\right)}^2}-3\left(1\right)+2\left(1\right)=1-3+2=0$