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Question

Find the numerical value of the letters given below
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Solution

Given, product of DE and 3=FDE
Since DE is multiple of 3 we need to find the number such that numbers D,E exists in the product value. By trial and error method we get
D=5 and E=0
And the product of 50×3=150
F=1 and D,E numbers exists in the value 150
Hence, D=5,E=0 and F=1

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