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Question
Find the odd and even extensions of f(x) = x4−x3+x2 (x > 0)
[ Assume the domain and range is x < 0 of the following function ]
Find the odd and even extensions of f(x) = x4−x3+x2 (x > 0)
[ Assume the domain and range is x < 0 of the following function ]
odd = 
, even = 
odd = 
, even = 
odd = 
, even = 
odd = 
, even = 
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Solution
The correct option is A odd = , even =
Even extention of f(x): f(-x) = x4+x3+x2, x < 0
Odd extention of f(x): -f(-x) = −x4−x3−x2, x < 0
odd = , even =
Even extention of f(x): f(-x) = x4+x3+x2, x < 0
Odd extention of f(x): -f(-x) = −x4−x3−x2, x < 0
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