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Question

Find the of tan10tan20tan30......tan450....tan800tan890

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Solution

The given expression can be written as (tan10tan890) (tan20tan880)....(tan440tan460)tan450
Now tan890=cot10,tan880=cot20 etc.
and tan450=1
(tan10cot10).(tan20cot20).....(tan440cot440)×1=1×1×1........×1=1

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