Find the order and degree of - d2x-dt2 -3 - - dx-dt -4 - xt - 0-

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Degree of a Differential Equations

Find the orde...

Question

Find the order and degree of ${[\frac{d^{2} x}{d t^{2}}]}^{3} + {[\frac{d x}{d t}]}^{4} - x t = 0$ .

2, 3

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3, 2

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4, 2

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2, 4

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Solution

The correct option is A $2, 3$

State the order and degree of the following differential equations
${[\frac{d^{2} x}{d t^{2}}]}^{3} + {[\frac{d x}{d t}]}^{4} - x t = 0$
Highest order derivative of equation is order which is 2 here.
Power of highest order derivative is degree which is 3 here.
So, ORDER= $2$
DEGREE= $3$

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Find the order and degree of [d2xdt2]3+[dxdt]4−xt=0.

The correct option is A 2,3State the order and degree of the following differential equations[d2xdt2]3+[dxdt]4−xt=0Highest order derivative of equation is order which is 2 here.Power of highest order derivative is degree which is 3 here.So, ORDER=2 DEGREE=3

Find the order and degree of ${[\frac{d^{2} x}{d t^{2}}]}^{3} + {[\frac{d x}{d t}]}^{4} - x t = 0$ .