Find the order and degree of the differential equation,
$y_{2}^{\frac{3}{2}} + y_{1} = 1$ .

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Solution

Given,
$y_{2}^{\frac{3}{2}} + y_{1} = 1$
or, $y_{2}^{\frac{3}{2}} = 1 - y_{1}$
or, $y_{2}^{3} = (1 - y_{1})^{2}$ .
From this we have, the order of the differential equation is $2$ and degree of the differential equation is $3$ .

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