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Question

Find the order and the degree of the differential equation:
[1+(dydx)2]32=5d2ydx2.

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Solution

Given the differential equation,
[1+(dydx)2]32=5d2ydx2
or, [1+(dydx)2]3=25(d2ydx2)2.
From the differential equation it is clear that the highest order term is the second order term on the right-hand side so the order of the differential equation is 2 and the power of the highest order term is 2 so degree of the differential equation is 2.

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