Find the order of reaction having rate law, rate = $k [N O]^{2} [H_{2}]$

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Solution

The Order of reaction for the following rate law is 1 + 2 = '3'

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H_{2} (g) + 2 I C l (g) \to I_{2} (g) + 2 H C l (g)

= k [H_{2}] [I C l]

2 H_{2 (g)} + 2 N O_{(g)} \to N_{2 (g)} + 2 H_{2} O_{(g)}

\frac{d [N_{2}]}{d t} = k [H_{2}] [N O]^{2}

2 H_{2} (g) + 2 N O (g) \to N_{2} (g) + 2 H_{2} O (g)

R a t e = k [H_{2}] [N O]^{2}

2 N O (g) ⇌ N_{2} O_{2} (g)

N_{2} O_{2} + H_{2} \to N_{2} O + H_{2} O

N_{2} O + H_{2} \to H_{2} O + N_{2}

What is the rate law for a second order reaction: 2A → Products

2 H_{2} + 2 N O \to 2 H_{2} O + N_{2}

r a t e = k [H_{2}] [N O]^{2}

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