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Byju's Answer
Standard XII
Chemistry
Valency and Oxidation State
Find the oxid...
Question
Find the oxidation and reduction process for the following reaction:
C
H
2
=
C
H
2
+
H
2
→
C
H
3
−
C
H
3
Open in App
Solution
Oxidation state of
C
in
C
2
H
4
=
−
2
Oxidation state of
H
in
H
2
=
0
Oxidation state of
H
in
C
2
H
6
=
+
1
Oxidation state of
C
in
C
2
H
6
=
−
3
Therefore,
oxidation process
:
C
H
2
=
C
H
2
→
C
H
3
−
C
H
3
Reduction process
:
H
2
→
C
H
3
−
C
H
3
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0
Similar questions
Q.
Explain the mechanism of the following reaction:
C
H
3
−
C
H
2
−
O
H
H
+
−
−
→
443
K
C
H
2
=
C
H
2
+
H
−
2
O
Q.
Match the column
A
,
B
and
C
suitably.
Reactabts
(
A
)
Products
(
B
)
Name of the reaction
(
C
)
C
H
3
−
C
H
3
+
C
l
2
C
O
2
+
H
2
O
Addition reaction
C
2
H
6
+
O
2
C
H
2
=
C
H
2
Thermal cracking
n
C
H
2
=
C
H
2
C
H
2
=
C
H
2
+
C
H
4
Substitution reactions
C
H
3
−
C
H
2
−
C
H
3
C
H
3
−
C
H
2
C
l
+
H
C
l
Polymerisation
C
H
≡
C
H
+
H
2
[
−
C
H
2
−
C
H
2
−
]
n
Combustion
Q.
Identify the type of the following reaction of carbon compounds.
a. CH
3
-CH
2
-CH
2
-OH → CH
3
-CH
2
-COOH
b. CH
3
-CH
2
-CH
3
→ 3CO
2
+ 4H
2
O
c. CH
3
-CH = CH -CH
3
+ Br
2
→ CH
3
-CHBr - CHBr -CH
3
d. CH
3
-CH
3
+ Cl
2
→ CH
3
-CH
2
-Cl + HCl
e. CH
3
-CH
2
-CH
2
-CH
2
-OH → CH
3
-CH
2
-CH=CH
2
+ H
2
O
f. CH
3
-CH
2
-COOH + NaOH → CH
3
-CH
2
-COO - Na
+
+ H
2
O
g. CH
3
-COOH + CH
3
-OH → CH
3
-COO- CH
3
+ H
2
O
Q.
Which of the following reaction is example of
S
N
2
reaction using
c
o
n
c
.
H
C
l
:
(
a
)
C
H
3
−
C
H
2
−
O
H
A
n
h
y
Z
n
C
l
2
/
△
−
−−−−−−−−
→
C
H
3
−
C
H
2
−
C
l
(
b
)
C
H
3
−
C
H
3
|
C
|
C
H
3
−
C
H
2
O
H
A
n
h
y
Z
n
C
l
2
/
△
−
−−−−−−−−
→
C
H
3
−
C
H
1
|
C
|
C
H
3
−
C
H
2
−
C
H
3
(
c
)
C
H
3
−
O
H
|
C
|
C
H
3
−
C
H
3
A
n
h
y
Z
n
C
l
2
/
△
−
−−−−−−−−
→
C
H
3
−
C
l
|
C
|
C
H
3
−
C
H
3
(
d
)
C
H
2
=
C
H
−
C
H
2
−
O
H
A
n
h
y
Z
n
C
l
2
/
△
−
−−−−−−−−
→
C
H
2
=
C
H
−
C
H
2
−
C
l
Q.
Which of the following reaction is example of
S
N
2
reaction using
c
o
n
c
.
H
C
l
:
(
a
)
C
H
3
−
C
H
2
−
O
H
A
n
h
y
Z
n
C
l
2
/
△
−
−−−−−−−−
→
C
H
3
−
C
H
2
−
C
l
(
b
)
C
H
3
−
C
H
3
|
C
|
C
H
3
−
C
H
2
O
H
A
n
h
y
Z
n
C
l
2
/
△
−
−−−−−−−−
→
C
H
3
−
C
H
1
|
C
|
C
H
3
−
C
H
2
−
C
H
3
(
c
)
C
H
3
−
O
H
|
C
|
C
H
3
−
C
H
3
A
n
h
y
Z
n
C
l
2
/
△
−
−−−−−−−−
→
C
H
3
−
C
l
|
C
|
C
H
3
−
C
H
3
(
d
)
C
H
2
=
C
H
−
C
H
2
−
O
H
A
n
h
y
Z
n
C
l
2
/
△
−
−−−−−−−−
→
C
H
2
=
C
H
−
C
H
2
−
C
l
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