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Question

Find the oxidation number of Carbon in Glucose C6H12O6


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Solution

Step-1 Calculating the charge on C6H12O6

  • Sugar is a neutral organic compound in nature.
  • Therefore the overall charge on Sugar = 0

Step-2 Calculating the oxidation number of Cabon in GlucoseC6H12O6-:

  1. As per standard, the oxidation number on HydrogenH= +1
  2. The oxidation number on OxygenO= -2
  3. The oxidation number on Carbon C = x
    FormalChargeonSugar=6×OxidationnumberofC+6×OxidationnumberofO+12×OxidationnumberofH

0=6×x+12×1+6×-2

0=6x+1212

6x=0x=0


Hence, the oxidation number of Carbon in C6H12O6 is 0.


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