Find the oxidation number of elements in each case .

$O$ in $O_{2}, O_{3}, O F_{2}$ and $B a O_{2}$ .

0, 0, + 2, - 1

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0, 0, + 2, + 1

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0, 0, + 1, 0

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None of the above

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Solution

The correct option is C $0, 0, + 2, - 1$
The oxidation number of $O$ in $O_{2}, O_{3}, O F_{2}$ and $B a O_{2}$ are $0, 0, + 2, - 1$ respectively.
Let X be the oxidation number of oxygen in $O_{2}$
$2 X = 0$
$X = 0$
Let X be the oxidation number of oxygen in $O_{3}$
$3 X = 0$
$X = 0$
Let X be the oxidation number of oxygen in $O F_{2}$
$X - 2 = 0$
$X = + 2$
Let X be the oxidation number of oxygen in $B a O_{2}$
$2 + 2 X = 0$
$X = - 1$

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P

(1, 0)

(0, 0)

1 : 2

y = - 3 x^{2}

O = (0, 0), A = (1, 0)

B = (\frac{1}{2}, \frac{\sqrt{3}}{2})

x^{2} + y^{2} = 9

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