Find the oxidation number of $N$ & $C l$ in $N O C l_{4}$ respectively is:

+ 3, + 6

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+ 2, + 6

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+ 3, + 7

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+ 2, + 7

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Solution

The correct option is D $+ 3, + 7$
$N O C l_{4}$ is made up of $N O^{+}$ and $C l O_{4}^{-}$
$N O^{+}$ x+1(-2)=+1
x=+3
$C l O_{4}^{-}$ x-8=-1
x=+7

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Question 6

Which of the following expressions show that rational numbers are associative under multiplication.
(a) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5}$
(b) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = \frac{2}{3} \times (\frac{3}{5} \times \frac{- 6}{7})$
(c) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{3}{5} \times \frac{2}{3}) \times \frac{- 6}{7}$
(d) $(\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5} = (\frac{- 6}{7} \times \frac{2}{3}) \times \frac{3}{5}$

The medians for the first 7 natural numbers (1, 2, 3, 4, 5, 6, 7) and the first 6 natural numbers (1, 2, 3, 4, 5, 6) respectively are _____ .

Question 6

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Find the oxidation number of N & Cl in NOCl4 respectively is:

The correct option is D +3,+7NOCl4 is made up of NO+ and ClO−4NO+ x+1(-2)=+1 x=+3ClO−4 x-8=-1 x=+7

Find the oxidation number of $N$ & $C l$ in $N O C l_{4}$ respectively is:

The correct option is D $+ 3, + 7$
$N O C l_{4}$ is made up of $N O^{+}$ and $C l O_{4}^{-}$
$N O^{+}$ x+1(-2)=+1
x=+3
$C l O_{4}^{-}$ x-8=-1
x=+7