Find the oxidation number of P in $M g_{2} P_{2} O_{7}$ .

Open in App

Solution

Let X be the oxidation number of P in $M g_{2} P_{2} O_{7}$ .
The Mg atoms have oxidation number of +2.
The O atoms have oxidation number of -2.
$2 (+ 2) + 2 X + 7 (- 2) = 0$
$2 X - 10 = 0$
$2 X = 10$
$X = + 5$
The oxidation number of P in $M g_{2} P_{2} O_{7}$ is $+ 5$ .

Suggest Corrections

Similar questions

M g_{2} P_{2} O_{7}

M g_{2} P_{2} O_{7}

M g_{2} P_{2} O_{7}

M g_{2} {P - -}_{2} O_{7}

N a_{2} [F e (C N)_{5} N O], K_{2} T a F_{7}, M g_{2} P_{2} O_{7}, N a_{2} S_{4} O_{6}, N_{3} H

Join BYJU'S Learning Program