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Question

Find the oxidation number of P in P2O47.

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Solution

Let the oxidation number of P be x .
Oxidation number of oxygen is +2 and overall oxidation state of molecule is -4
In P2O47,

2x+7(2)=4
P O

2x14=4
2x=144
x=+5

Hence the oxidation number of P in P2O47 is +5.


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