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Question

Find the oxidation number of S in H2S2O8.

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Solution

Let X be the oxidation number of S in H2S2O8.
One peroxo linkage is present which is OO linkage. The O atoms of this linkage have oxidation number of -1. The remaining O atoms have oxidation number of -2.
The oxidation number of H is +1.
2(+1)+2X+2(1)+6(2)=0
2X12=0
2X=12
X=+6
The oxidation number of S in H2S2O8 is +6.

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