The correct option is A +4
Valency of each oxygen which is having single bond with sulphur will be considered as -1 and which is having double bond will be considered -2.
We can see molecule overall is neutral.
Let the oxidation number of sulphur which is bonded with 3 oxygens is x.
⇒x+1×(−1)+2×(−2)=0
⇒x=+5
Let the oxidation number of sulphur which is bonded with 2 oxygens is y.
⇒y+1×(−1)+1×(−2)=0
⇒y=+3
Average oxidation state of sulphur= x+y2=+4
Thus, Average oxidation state of sulphur is +4.