Find the oxidation state of $M n$ in $K M n O_{4}$ ?

-7

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-3

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Solution

The correct option is D 7
Oxidation state of $M n$ in $K M n O_{4}$ .
Let the $M n$ has oxidation state to be x.
$K$ has +1, $O$ has -2 oxidation state.
$+ 1 + 4 \times (- 2)$ +x = 0
x $= + 7$

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