Question

Find the parametric equation of the circle
$x^2+y^2+x+\sqrt{3y}=0$

Answer 1

The given circle is $(-\frac{1}{2},-\frac{\sqrt{3}}{2})$ , 1
or ${(x+\frac{1}{2})}^2+{(y+\frac{\sqrt{3}}{2})}^2=r^2=1^2$
${(x+\frac{1}{2})}^2+{(y+\frac{\sqrt{3}}{2})}^2=r^2=1^2$
Its parametric equations are given by
$x+\frac{1}{2}$ = r cos $\theta =cos\theta$
$y+\frac{\sqrt{3}}{2}=rsin\theta =sin\theta$