Question

Find the percentage of P in super phosphate of lime.

• A. 6.82%
• B. 18.35%
• C. 11.25%
• D. 25.3%

Answer 1

Answer: (C)

11.25%

Mol. wt of super phosphate of lime
$=3[40+[(2\times 1)+31+16\times 4]\times 2]+7[40+32+(16\times 4\left)\right]$
$=3[40+194]+7\left[136\right]$
$=702+952$
$=1654$
% of P in super phosphate of lime
$\frac{186\times 100}{1654}=11.25$%