Find the percentage of P in super phosphate of lime.
A
6.82%
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B
18.35%
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C
11.25%
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D
25.3%
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Solution
The correct option is D 11.25% Mol. wt of super phosphate of lime =3[40+[(2×1)+31+16×4]×2]+7[40+32+(16×4)] =3[40+194]+7[136] =702+952 =1654 % of P in super phosphate of lime 186×1001654=11.25%