Find the perimeter and area of rectangle with the following dimensions:
Length = $800 k m$ and breadth= $250 m$

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Solution

Step1: Conversion of unit
Given: Length= $800 k m$ and breadth= $250 m$
As length and breadth are not in same unit so we need to convert any one of them.
As we know,
$1 k m$ = $1000 m$
so we convert $800 k m$ into $m$
length= $800 \times 1000$
= $800000 m$
Step2: Find the perimeter of the rectangle:
Perimeter of rectangle = $2 (l e n g t h + b r e a d t h)$
= $2 (800000 + 250)$
= $2 (800250)$
= $2 \times 800250$
= $1600500 m$ $(1 m = \frac{1}{1000} k m a n d 1600500 k m = \frac{1600500}{1000})$
= $1600.5 k m$
Step3: Finding the area of the rectangle:
Area of rectangle = $l e n g t h \times b r e a d t h$
= $800000 \times 250$
= $200000000 s q m$ $(200000000 s q m = \frac{200000000}{1000} \times 1000 = 200 s q k m)$
= $200 s q k m$
Therefore, perimeter of the rectangle is $1600.5 k m$ and the area of the rectangle is $200 s q k m$ .

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