Question

Find the perimeter and the area of the right angled triangle whose sides are 6 feet, 8 feet and 10 feet. ?

Answer 1

Perimeter of the triangle

= (a + b + c) units

= (6 + 8 + 10) feet

= 24 feet

Area of the triangle $=\frac{1}{2}\times b\times h$ sq unit

$=\frac{1}{2}\times 6\times 8$ feet square

= 24 sq. feet