Find the perimeter of a $∆ A B C$ whose:
$A B = 2 m 75 c m, B C = 3 c m, C A = 2 m 60 c m$

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Solution

Step 1: Convert given data into same units
Given, $A B = 2 m 75 c m, B C = 3 c m, C A = 2 m 60 c m$
$A B = 2 + \frac{75}{100} = 2 + 0.75 = 2.75 m B C = 0.03 m$
$A C = 2 + \frac{60}{100} = 2 + 0.60 = 2.60 m$
Step 2: Find the perimeter of a $∆ A B C$
Perimeter of $∆ A B C$ $= A B + B C + C A$
$= 2.75 + 0.03 + 2.60 = 5.38 m$
$= 5 m 38 c m$
Hence, perimeter of a $∆ A B C$ is $5 m 38 c m$ .

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