Find the perimeter of a rectangle if one of its sides is $24 c m$ and a diagonal is $25 c m$ . There are two poles in a garden which are $36 m$ apart. If the poles are $15 m$ and $10 m$ high. Find the distance between their tops.

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Solution

Second side $= \sqrt{25^{2} - 24^{2}} = 7 c m$
Area $= 7 \times 24 = 168 {c m}^{2}$
Perimeter $= (7 + 24) \times 2 = 62 c m$

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Find the perimeter of a rectangle if one of its sides is 24 cm and a diagonal is 25 cm. There are two poles in a garden which are 36 m apart. If the poles are 15 m and 10 m high. Find the distance between their tops.

Second side =√252−242=7cmArea =7×24=168cm2Perimeter =(7+24)×2=62cm

Find the perimeter of a rectangle if one of its sides is $24 c m$ and a diagonal is $25 c m$ . There are two poles in a garden which are $36 m$ apart. If the poles are $15 m$ and $10 m$ high. Find the distance between their tops.

Second side $= \sqrt{25^{2} - 24^{2}} = 7 c m$
Area $= 7 \times 24 = 168 {c m}^{2}$
Perimeter $= (7 + 24) \times 2 = 62 c m$