Question

Find the perimeter of a rectangle in which:
(i) length = 16.8 cm and breadth = 6.2 cm
(ii) length = 2 m 25 cm and breadth = 1 m 50 cm
(iii) length = 8 m 5 dm and breadth = 6 m 8 dm

Answer 1

We know: Perimeter of a rectangle = $2\times (\mathrm{Length}+\mathrm{Breadth})$

(i) Length = 16.8 cm
Breadth = 6.2 cm
Perimeter = $2\times (\mathrm{Length}+\mathrm{Breadth})$
= $2\times (16.8+6.2)=46\mathrm{cm}$
(ii) Length = 2 m 25 cm
=(200+25) cm (1 m = 100 cm )
= 225 cm
Breadth =1 m 50 cm
= (100+50) cm (1 m = 100 cm )
= 150 cm
Perimeter = $2\times (\mathrm{Length}+\mathrm{Breadth})$
= $2\times (225+150)=750\mathrm{cm}$
(iii) Length = 8 m 5 dm
= (80+5) dm (1 m = 10 dm )
= 85 dm
Breadth = 6 m 8 dm
= (60+8) dm (1 m = 10 dm )
= 68 dm
Perimeter = $2\times (\mathrm{Length}+\mathrm{Breadth})$
= $2\times (85+68)=306\mathrm{dm}$