Find the perimeter of a rectangle whose area is 500 cm 2 and breadth is 20 cm-

Area = 500 cm2 Breadth = 20 cm Area of rectangle = Length #215; nbsp;Breadth Therefore Length = Area #160;Breadth= 50020 = 25 cm Perimeter of a rectangle ...

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Standard VI

Mathematics

Perimeter of Rectangle

Find the peri...

Question

Find the perimeter of a rectangle whose area is 500 cm² and breadth is 20 cm.

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Solution

Area = 500 cm²
Breadth = 20 cm
Area of rectangle = Length $\times$ Breadth
Therefore
Length = $\frac{A r e a}{B r e a d t h}$ = $\frac{500}{20}$ = 25 cm
Perimeter of a rectangle = 2 (Length + Breadth)
= 2 (25 + 20) cm = 2 $\times$ 45 cm = 90 cm

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Find the perimeter of a rectangle whose area is 500 cm2 and breadth is 20 cm.

Area = 500 cm2 Breadth = 20 cm Area of rectangle = Length × Breadth Therefore Length = Area Breadth= 50020 = 25 cm Perimeter of a rectangle = 2 (Length + Breadth) = 2 (25 + 20) cm = 2 × 45 cm = 90 cm

Find the perimeter of a rectangle whose area is 500 cm² and breadth is 20 cm.

Area = 500 cm²
Breadth = 20 cm
Area of rectangle = Length $\times$ Breadth
Therefore
Length = $\frac{A r e a}{B r e a d t h}$ = $\frac{500}{20}$ = 25 cm
Perimeter of a rectangle = 2 (Length + Breadth)
= 2 (25 + 20) cm = 2 $\times$ 45 cm = 90 cm