Find the perimeter of a rectangle whose two adjacent sides are
$5 x^{2} + 2 x y - 13; 2 x^{2} - 6 x y + 11$

14 x^{2} - 8 x y - 4

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x^{2} - 8 x y - 3

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4 x^{2} - 8 x y - 3

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12 x^{2} - 8 x y - 4

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Solution

The correct option is A $14 x^{2} - 8 x y - 4$
Perimeter of a rectangle is $2 (L + B)$ , where $L$ = Length and $B$ = Breadth
Given, two adjacent sides are $5 x^{2} + 2 x y - 13, 2 x^{2} - 6 x y + 11$
Therefore,
$2 (L + B)$
$= 2 (5 x^{2} + 2 x y - 13 + 2 x^{2} - 6 x y + 11)$
$= 2 (7 x^{2} - 4 x y - 2)$
$= 14 x^{2} - 8 x y - 4$

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